'Spintronics' sounds like it is spin in the metaphorical sense of the word;)
At least it sounds like that when stated as in this article: losses do NOT result from current flow, they result from the Second Law of Thermodynamics. You will have them even WITHOUT current flow through resistors.
Now the losses may prove dramatically less than in ohmic conductors, but we won't know for sure until devices are constructed.
Or until someone does a COMPLETE analysis of the thermodynamics of 'spintronics'. But if we had that, we wouldn't have been surprised by the output in this article, would we?
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