If the supply voltage falls by 50% the current also falls by 50% and assuming (wrongly)that the load is resistive. The power falls to 25% (1/2 Volts X 1/2 Amps = 1/4 VA).
Maybe we should move to dedicated DC circuits supplied by solar and mains electricity but with large capacity
battery storage.This would require careful use of fuses
and current monitoring circuitry; old technology updated.
Discussion on:
Message 12 of 1
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